- The Washington Times - Wednesday, November 6, 2019

Baltimore Ravens quarterback Lamar Jackson was named AFC Player of the Week on Wednesday for his performance against the New England Patriots. 

Jackson scored three touchdowns — one through the air, two on the ground — en route to handing New England its first loss of the season. The victory helped put Jackson in the MVP conversation as the league’s first-ranked defense had trouble stopping the shifty quarterback.

This is the second time Jackson has won the award this season. He also earned the honor in a Week 1 win over the Miami Dolphins, when he threw five touchdowns. 

The Ravens are 6-2 in 2019, and sit atop the AFC North. 

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