- The Washington Times - Friday, September 25, 2020

President Trump signed an executive order Friday night to ensure that every infant born alive, including extremely premature or disabled babies, receives medical care.

“It is the policy of the United States to recognize the human dignity and inherent worth of every newborn or other infant child, regardless of prematurity or disability, and to ensure for each child due protection under the law,” the president wrote in the order.

Mr. Trump said during the National Catholic Prayer Breakfast this week that he intended to sign the order.

Despite federal laws protecting the rights of infants, the president said, “some hospitals refuse the required medical screening examination and stabilizing treatment or otherwise do not provide potentially lifesaving medical treatment to extremely premature or disabled infants, even when parents plead for such treatment.”

“Hospitals might refuse to provide treatment to extremely premature infants — born alive before 24 weeks of gestation — because they believe these infants may not survive, may have to live with long-term disabilities, or may have a quality-of-life deemed to be inadequate,” he said. “Active treatment of extremely premature infants has, however, been shown to improve their survival rates. And the denial of such treatment, or discouragement of parents from seeking such treatment for their children, devalues the lives of these children and may violate federal law.”



He said such infants “are entitled to meaningful and non-discriminatory access to medical examination and services, with the consent of a parent or guardian, when they present at hospitals receiving Federal funds.”

Sign up for Daily Newsletters

Manage Newsletters

Copyright © 2020 The Washington Times, LLC. Click here for reprint permission.

Please read our comment policy before commenting.

 

Click to Read More and View Comments

Click to Hide